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[spoiler alert]

The #s is brilliantly misleading. A shorter version is

  #x0#s0  ;==> 0.0f0 (almost like 0.0)

In this case, the second # means an unspecified digit in an inexact number. For example

  4## ;==> 400.0 

(other scheme implementation may give a different result near 400, like 450.0)

The s is the exponent mark in a single precision number

  2s4 ;==> 20000.0f0

First of all the `@` means we are dealing with a an inexact

    ‹inexact-complexn› ::= ‹inexact-realn› @ ‹inexact-realn›

Here is a short guide: #e means exact #x means hexadecimal

So `#e#x+e` means exact 14.

The last `#` in means an unknown number - Racket has chosen to use 0. Therefore `#e#x+e#` means 1416 = 224.

The `s0` is an exponent mark, which marks the precision of an inexact number. The `s0` means single-precision (in Scheme s means short - in many implementations short and single both use single precision).

Thus `#x+e#s0` means `224.0f` and `#e#x+e#s0` means 224.

Now since it is a hexadecimal number the following `+e` means 14. Therefore `#e#x+e#s0+e` means `22416^14` which is 16140901064495857664.

Now we come the `@`. This means the first part was the real part of a complex number and what follows is the imaginary part.